Cycle indices of some permutation groups
Identity group En
This group contains one permutation that fixes every element (this must be a natural action).
Z(En)=a1n.
Cyclic group Cn
A Cyclic group, Cn is the group of rotations of a regular n-gon, that is, n elements equally spaced around a circle. This group has φ(d) elements of order d for each divisor d of n, where φ(d) is the Euler φ-function, giving the number of natural numbers less than d which are relatively prime to d. In the regular representation of Cn, a permutation of order d has n/d cycles of length d, thus
Z(Cn)=n1d∣n∑φ(d)adn/d.
Dihedral group Dn
The Dihedral group is like the cyclic group, but also includes reflections. In its natural action,
Z(Dn)=21Z(Cn)+{21a1a2(n−1)/2,41(a12a2(n−2)/2+a2n/2),n\mboxodd,n\mboxeven.
The alternating group An
The cycle index of the alternating group in its natural action as a permutation group is
Z(An)=j1+2j2+3j3+⋯+njn=n∑∏k=1nkjkjk!1+(−1)j2+j4+⋯k=1∏nakjk.
The numerator is 2 for the even permutations, and 0 for the odd permutations. The 2 is needed because
∣An∣1=n!2.
The symmetric group Sn
The cycle index of the symmetric groupSn in its natural action is given by the formula
Z(Sn)=j1+2j2+3j3+⋯+njn=n∑∏k=1nkjkjk!1k=1∏nakjk.
This formula is obtained by counting how many times a given permutation shape can occur. There are three steps: first partition the set of n labels into subsets, where there are jk subsets of size k. Every such subset generates k!/k cycles of length k. But we do not distinguish between cycles of the same size, i.e. they are permuted by Sjk. This yields
∏k=1n(k!)jkn!k=1∏n(kk!)jkk=1∏njk!1=∏k=1nkjkjk!n!.
There is a useful recursive formula for the cycle index of the symmetric group.
Set Z(S0)=1 and consider the size l of the cycle that contains n,
where 1≤l≤n. There are (l−1n−1) ways to choose the remaining l−1 elements of the cycle and every such choice generates ll! different cycles.
This yields the recurrence
Z(Sn)=n!1g∈Sn∑k=1∏nakjk(g)=n!1l=1∑n(l−1n−1)ll!al(n−l)!Z(Sn−l)
or
Z(Sn)=n1l=1∑nalZ(Sn−l).
See also